if inside printf function

Program

#include <stdio.h> int main() { if(printf("hi\\n")) { printf("welcome\\n") ; } else { printf("Hello\\n") ; } }

Here's a step-by-step explanation of what this code does:

1. printf("hi\\n"):
   The printf function prints the string "hi\\n" to the standard output (usually the terminal or console).
   printf returns the number of characters printed. In this case, "hi\\n" has 3 characters ('h', 'i', and '\\n'), so printf returns 3.
2. if(printf("hi\\n")):
   The if statement checks the return value of printf("hi\\n"). Since printf returns 3 (which is non-zero), the condition evaluates to true.
3. Inside the if block:
   Because the condition is true, the code inside the if block is executed. Thus, printf("welcome\\n"); is called, which prints "welcome\\n" to the standard output.
4. The else block:
   Since the if condition was true, the else block is skipped and the printf("Hello\\n"); inside the else block is not executed.

Summary:

• The program first prints "hi\\n".
• Then, it prints "welcome\\n".
• The "Hello\\n" message is not printed because the else block is not reached.

Output of the program:
hi
welcome